Question

A bus decreases its speed from 80kmh-1 to 60kmh -1 in 5 seconds . Find acceleration and distance​

Answer 1

Answer:

Acceleration = -4 kmh-2

Distance = 50 km

Explanation:

Initial Speed of the bus (u) = 80 km h-1

Final Speed of the bus (v) = 60 km h-1

Time Interval of Retardation (t) = 5 seconds

Acceleration = (v-u)/t = (60-80)/5 = -20/5 = -4 km h-2

Distance =  1/2 * (80 - 60) * 5 = 1/2 * 20 * 5 = 50 km