Physics, asked by archananirmalkar, 8 months ago

A bus devieases its speed 80 km/h to 60 km/h in
5 sec. find the acceleration of bus​

Answers

Answered by BrainlyBat
0

the first stanza of the novel in the test of the polynomial 4was 4the world

Answered by Cynefin
4

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✰Answer✰

♦️GiveN

  • Speed decreases from 80 km/h to 60km/h
  • Time taken is 5 sec.

♦️To FinD

  • Accleration of the bus...?

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⭐As we can see the unit of speed in in kilometer/hr and the time taken is in seconds, Thus we need to convert tge units first for further Calculation.

✰Unit Conversion✰

➯Changing Speed in km/h to m/s,

 \large{ \tt{ \rightarrow \: 80 \: kmh {}^{ - 1}  = 80 \times  \frac{5}{18} ms {}^{ - 1} }} \\  \\  \large{ \tt{ \rightarrow \: 80 \: km {h}^{ - 1}  =  \cancel{ \frac{400}{18} m {s}^{ - 1} }}} \\  \\  \large{ \rightarrow \:  \boxed{ \tt{ \purple{80 \: kmh {}^{ - 1}  =  \frac{200}{9} m {s}^{ - 1} }}}}  \\  \\  \\  \large{ \tt{ \rightarrow \: 60 \: km {h}^{ - 1}  = 60 \times  \frac{5}{18} m {s}^{ - 1} }} \\  \\  \large{ \tt{ \rightarrow \: 60 \: km {h}^{ - 1}  =  \cancel{\frac{300}{18} m {s}^{ - 1} }} }\\  \\  \large{ \tt{ \rightarrow \:  \boxed{ \purple{ \tt{60 \: km {h}^{ - 1}  =   \frac{150}{9} m {s}^{ - 1} }}}}}

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♦️We multiply 5/18 because

 \large{ \tt{1km = 1000m}} \\  \\  \large{ \tt{1 hr = 3600s}}  \\  \\  \large{ \tt{1 \: kmh {}^{ - 1}  =  \frac{1000}{3600} m {s}^{ - 1} =  \frac{5}{18} \: m {s}^{ - 1}  }}

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Solution

We have,

  • Initial velocity( u )= 200/9 m/s
  • Final velocity(v) = 150/9 m/s
  • Time taken(t) = 5 sec

➯By using 1st equation of motion,

 \large{ \star{ \boxed{ \tt{ \green{v = u + at}}}}}

♦️Note: Symbols have their usual meanings.

By using the above equation,

 \large{ \tt{  \rightarrow \: \frac{150}{9}  =  \frac{200}{9}  +  \: a \times 5}} \\  \\  \large{ \tt{ \rightarrow \:  \frac{ - 50}{9} =  5a}} \\  \\  \large{ \tt{ \rightarrow \: a =  \frac{ \cancel{- 50} \:  - 10}{9 \times  \cancel{5}} }} \\  \\  \large{ \rightarrow  \boxed{ \purple{ \tt{\: a =  - 1 .  \bar{1} \: m {s}^{ - 2} }}}}

 \large{ \tt{ \star{ \orange{ \: accleration \: of \: the \: body =  - 1 \bar{.1}}}}}

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