Question

A particle moving along a straight line has velocity which varies with time is v = |t
^2
– 5t + 4|, then acceleration of

the particle at t = 2s is?​

Answer 1

Explanation:

acceleration is the differentiation of velocity

dv/dt = a

So as per question

t²-5t+4

dv/dt is 2t-5

Therefore by putting the value of t=2

=-1