A bus driver filled the bus tank with 23L OF DIESEL. Two later he filled the tank with 24L of the diesel. If the diesel costs 38 RS per L, how much did he spend in all on diesel?
(Use distributive property )
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23 L of diesel was first filled in the bus tank by the driver.
The cost of diesel is Rs 38 per L.
So the cost of 23 L = 23 × 38 = Rs 874
Then he again filled the tank with 24 L of diesel.
So the cost of 24 L of diesel = 24 × 38 = Rs 912
Total cost for the diesel = 874 + 912 = Rs 1786
By using distributive property ,
[a+b]c = a×b + a×c
Here , a = 24 , b = 23 and c= 38
So , [24+23]38 = 24×38 + 23×38 = 874 + 912 = 1786
So the same answer.
The cost of diesel is Rs 38 per L.
So the cost of 23 L = 23 × 38 = Rs 874
Then he again filled the tank with 24 L of diesel.
So the cost of 24 L of diesel = 24 × 38 = Rs 912
Total cost for the diesel = 874 + 912 = Rs 1786
By using distributive property ,
[a+b]c = a×b + a×c
Here , a = 24 , b = 23 and c= 38
So , [24+23]38 = 24×38 + 23×38 = 874 + 912 = 1786
So the same answer.
Anonymous:
nice
Answered by
1
He filled diesel first = 23L of diesel
He Filled diesel second= 24L of diesel
Cost of 1L of diesel= 38Rs
Cost of 23L of diesel= 38 x 23
=874 Rs
Cost of 24L of diesel=24x 38
=912 Rs
total cost of the diesel filled in the bus= 874+912
=1,786
Hence, total cost of diesel filled in the bus is Rs 1,786
He Filled diesel second= 24L of diesel
Cost of 1L of diesel= 38Rs
Cost of 23L of diesel= 38 x 23
=874 Rs
Cost of 24L of diesel=24x 38
=912 Rs
total cost of the diesel filled in the bus= 874+912
=1,786
Hence, total cost of diesel filled in the bus is Rs 1,786
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