Question

A bus going at 36 km/h is stopped in 6 seconds by brakes. Calculate the acceleration. Pls add working

Answer 1

Answer:

- 1.67 m/s^2

Explanation:

According to the given question,

u = initial velocity = 36 km/h = 36×1000/3600 = 10 m/s

v = final velocity = 0 m/s

t = time = 6 sec

a = acceleration

And we are asked to find the acceleration of the bus.

We know,

• v = u+at

Putting the values we get,

• 0 = 10+6a

• 6a = -10

• a = - 10/6

• a = - 5/3

• a = - 1.67 m/s^2

Thus acceleration of the bus is - 1.67 m/s^2 from the given data.

Answer 2

Answer:

Acceleration = - 1.66 m/s²

Explanation:

Given-

• Initial velocity (v) = 0 m/s
• Final velocity (u) = 36 km/hr = 10 m/sec
• Time = 6 secs.

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To Find -

• Acceleration.

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Solution-

$\blue\bigstar$Formula -

$\tt\red{acceleration=\frac{v-u}{time}}$

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$\orange\bigstar$Answer -

Acceleration $= \frac{0 - 10}{6} \\ \\ = \frac{ - 10}{6} \\ \\ = \frac{ - 5}{3} \\ \\ = - 1.66$

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$\green\bigstar$Required Solution -

Acceleration is (-1.66 m/s²).