Question

a bus has 5 stops . it carries 60 passengers . at the first stop, 15 get down. at second stop 3 get down. at third stop half of the passengers get down while 10 more get down at The Fourth stop .how many passengers will get down at the last stop ?​

Answer 1

Answer:

11 passengers

Step-by-step explanation:

A bus has 5 stops.

The bus Carries 60 passenger.

At the first stop 15 get down

so,

Passengers remained after first stop

= Total passengers - passengers get down

= 60 - 15

= 45

At the second stop 3 get down

so,

Passengers remained after second stop

= Passengers first stop - passengers get down

= 45 - 3

= 42

At the third stop half of the passengers get down

so,

Passengers remained after third stop

= Passengers second stop - half of second stop

= 42 - (42/2)

= 42-21

= 21

At fourth stop 10 passengers get down

so,

passengers after fourth stop

= passengers third stop - passengers get down

= 21 - 10

= 11

How many passengers will get down at the last stop ?

Because bus has only 5 stops, so remaining all passengers will get down at the last stop.

Passengers remained = passengers after fourth stop = 11

Hence 11 passengers will get down at the last stop.

hope it helps.

Answer 2

Answer:

11

Step-by-step explanation:

hope it will be helpful to you