A bus increase its speedfrom 20km/h to50km/h in 10sec find its acceleration
Answers
Answered by
1
Starting Speed (u) = 20km/h = 20×(5/18) m/s = 100/18 = 50/9 m/s.
Last Speed (v) = 50km/h = 50×(5/18) m/s = 250/18 = 125/9 m/s.
And, Time (t) = 10 seconds.
So, Acceleration (a) = (v - u)/t
a = { (125/9) - (50/9) } / 10
a = 75/9×10
a = 75/90 = 5/6
Acceleration (a) = 0.8333 m/s........... ●
●●●●●●●●●●●●●●●
Hope it was helpful.
Last Speed (v) = 50km/h = 50×(5/18) m/s = 250/18 = 125/9 m/s.
And, Time (t) = 10 seconds.
So, Acceleration (a) = (v - u)/t
a = { (125/9) - (50/9) } / 10
a = 75/9×10
a = 75/90 = 5/6
Acceleration (a) = 0.8333 m/s........... ●
●●●●●●●●●●●●●●●
Hope it was helpful.
Answered by
3
Answer:
Explanation:
Acceleration=Change in speed/Time=(50-20)*(5/18)/10=0.83m/s^2,
hope you understood.
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