Question

a bus increases its speed from 36 km/hr to 54km/hr in 10 sec . find its accleration

Answer 1

u = 36 km/h = 36×5/18 = 10 m/s
v = 54 km/h = 54×5/18 = 15 m/s
t = 10 s
v = u+at
15 = 10 + 10a
10a = 15-10
10a = 5
a = 5/10
a = 0.5 m/s²

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Answer 2

"The acceleration of the bus after increasing it's speed is $1\frac { m }{ { s }^{ 2 } }$

Solution:

It is given that the initial speed of the bus ${ u }\quad =\quad 36{ km }/{ h\quad}=\quad 36\times \frac { 5 }{ 18 } \quad =\quad 10\quad \frac { m }{ s }$

and rise in speed of the $bus { v }\quad =\quad 54{ km }/{ h\quad}=\quad 54\times \frac { 5 }{ 18 } \quad =\quad 15\quad \frac { m }{ s }$

The increase in speed is done by $10\frac { m }{ s }$

t = 10 second

We know, v=u+at

$a=\frac { v-u }{ t }$

 $=\frac { 15-10 }{ 10 }$

$=\frac { 5 }{ 10 }$

 $=0.5\frac { m }{ { s }^{ 2 } }$"