Question

A bus initially at rest starts moving with an acceleration of 2 ms−22 ms−2 .The time in which it picks up a velocity of 32 ms−132 ms−1 is​

Answer 1

Answer:

Initial velocity, u=0

Acceleration, a=2ms^−2

Time, t=5s

Distance traveled, s=ut+1/2at^2

s=(0×5)+ (1/2×2×5^2) =25m

Answer 2

Answer:

Initial Velocity is u=0

Acceleration, a=2ms^-2

Time (t) =5s

Distance travelled, s=ut+ 1/2 at^2

s=(0×5)+ (1/2×2×5^2 = 25m

Hope this helps..