Question

A bus is moving at the speed of 40 2/5 km/h. how far will it travel in 6 2/3 hours?if the bus is still at a distance of 10 2/5km from the final destination; how far is the final destination from the starting point?

Answer 1

Speed of the bus,
$40 \frac{2}{5} = \frac{40 \times 5 + 2}{5} = \frac{202}{5}$
Which is equal to 40.4

Time taken,
$6 \frac{2}{3} = \frac{6 \times 3 + 2}{3} = \frac{20}{3}$
Which is equal to 6.6666..........

Distance travelled will be,
$\frac{202}{5} \times \frac{20}{3} = \frac{4040}{15}$
Therefore it travelled 269.3333..... distance.

Distance from the final point,
$10 \frac{2}{5} = \frac{10 \times 5 + 2}{5} = \frac{52}{5}$
Which is equal to 50.4


Distance from starting point to final point,
$\frac{4040}{15} + \frac{52}{5} = \frac{6744}{15} = 449.6$
Therefore the total distance from the starting point to final point is 449.6