Question

A bus is moving on a straight road with a uniform velocity of 36m/s. It undergoes uniform
retardation such that its velocity becomes 20 m/s after 4 seconds. Then it moves with a constant speed
of 20 m/s for next 4 seconds and then accelerates at the constant rate of 2m/s2 for 5 seconds.
Plot velocity – time graph for the motion of the bus. Using this graph, calculate
(i) retardation (ii) the distance covered by bus during zero acceleration and
(iii) final velocity at the end of 5 seconds of uniform positive acceleration.​

Answer 1

Answer:

Retardation = velocity decrease / time

= 16/4 = 4 m/s2

Distance covered = 20 x 4 = 80 m

Velocity at the end of 5 seconds = deceleration x time = 10 m/s

Answer 2

Answer:

Retardation=velocity decrease/time =16/4=4m/s

distance covered=20×4=80m

velocity at the end of 5 seconds = deacceleration×time=10m/s