Question

A bus is moving with a velocity of 36km/h and it comes to rest in 72 m with a constant retardation in 5 second. Find the retardation and the time taken?

Answer 1

Given :

u = 36 km/h = 10 m/s

v = 0

s = 72 m

t = 5 s

Using the equation of motion,

$v = u + at \\ a = \frac{v - u}{</u><u>t</u><u>} \\ a = \frac{0 - 10}{5} \\ a = \frac{ - 10}{5} = - 2 \: m {s}^{ - 2}$

Retardation = 2 ms^-2

Answer 2

Answer:

u initial speed =36km/hr

v final speed= 0

time t = 5 sec

v= u+at

0=36+a*t