A bus is moving with an initial velocity 'u' m/s. After applying brakes its retardation is 0.5m/s² and is stopped after 12s. find initial velocity 'u' and distance travelled by the bus after applying brakes
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안녕하세요!
v=0m/s (as it stops)
t=12s
a=-0.5m/s(retardation)
a=v-u/t
-0.5=0-u/12
-0.5*12=-u
u=6m/s
s=ut+1/2at^2
s=6*12+1/2*-0.5*12^2
s=72+1/2*-0.5*144
s=72-0.5*72
s=72-36
s=36m
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