Question

A bus is moving with speed of 54 km per hour on applying brake it stop in 8 seconds calculate acceleration and distance travel before stopping

Answer 1

I would do it this way:

We know out initial velocity (u) to be 54km/hr

(54 ×5/18)

Thus u= 15 m/s.

Time taken to stop = 8 seconds.

Thus t = 8s.

The bus stops completely. Thus final velocity,(v) = 0 m/s.

Now, we can use the equation:

v=u+at

Now v = 0 , u = 15 and t= 8.

=>0=15+8a.

Rearranging,

=>a=−15/8.

Thus acceleration comes to −1.875m/s2.

Now we know acceleration, time and initial velocity. Thus distance can be calculated as:

s=ut+(at2)/2.

=>s=15×8+(−1.875×64)/2.

Solving this, we get the distance to be 60m.

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