A can do a piece of work in 32 days while b can do it in 40 days after working together for 10 days b left in how many days will a finish the remaining work
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Answer:
Step-by-step explanation:
Let Total Work = LCM(32,48,96) = 96 units
A completes 3 unit in 1 day
B completes 2 unit in 1 day
C completes 1 unit in 1 day
Let the work be completed in x days.
C works for x days completing x units
B works for x - 9 days completing 2x - 18 units
A works for 9 days completing 27 units
Now x + 2x - 18 + 27 = 96 units
3x = 87
=> x = 29 days
:-)
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