a bus is running at speed of 18 km/hr is stopped in 2.5 sec. by applying brakes.calculate the produced?
Shravani83:
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Answers
Answered by
328
18 km/hr = 5 m/s
so we know v = u + at
so 0 = 5 + 2.5 a
so a = -5/2.5 = - 2 m/s²
so we know v = u + at
so 0 = 5 + 2.5 a
so a = -5/2.5 = - 2 m/s²
hope it helps
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hw come its minus??
Answered by
111
Answer:
Known terms:-
u = Initial speed
v = Final speed
a = Acceleration
r = Retardation
t = Time
Given:-
Initial speed of bus, u = 18 km/h = 5/18 × 18 = 5 m/s
Time taken by bus to stop after applying brakes, t = 2.5 sec
Final speed of bus, v = 0 m/s (Because when brakes applied then bus stops)
To Calculate:-
Retardation Produced.
Formula to be used:-
Newton's 1st equation that is v = u+at
Solution:-
Putting all values, we get
⇒ v = u + at
⇒ 0 = 5 + a(2.5)
⇒ a = -5/2.5
⇒ a = - 2 m/s²
Hence, Retardation Produced by bus is 2 m/s².
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