Question

a bus is starting from rest attain a value of 90 km/1 in 10 records calculate acceleration and distance covered.

Answer 1

initial velocity(u)= 0 m/s
final velocity(v)=90 km/hr=25 m/s
time=10 s
so,
a=(v-u)/t=25/10=2.5 m/s^2
and s=(v^2-u^2)/2a
s=625/5=125 m

PLZ MARK IT AS BRAINLIEST

Answer 2

Hello friend

Here's your answer

The bus has started from rest

So u=0

It attained a speed of 90km/h=90*5/18=25m/sec

So v=25

Time taken is 10seconds

Acceleration is the rate of change of velocity

It is given by a=(v-u)/t

=(25-0)/10

=25/10

=2.5m/s²

Using the equation of motion v²-u²=2as

(v²-u²)/2a=s

s=(25²-0²)/2*2.5

s=625/5

s=125m

Hope it helps!!