Question

A bus is traveling with a uniform acceleration of 2.75 meters/second2. If the initial velocity of the bus is 16.5 meters/second, what will its velocity be after 9.00 seconds?

Answer 1

41.25..v=u+at,u is initial velocity,a is acceleration.

Answer 2

hey here is your answer
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=$a = \frac{v - u}{t} \\= 2.75 \: m {s}^{ - 2} = \frac{v - 16.5 \: m {s}^{ - 1} }{9 \: s} \\= 2.75 \times 9 \: m {s}^{ - 1} = v - 16.5 \: m {s}^{ - 1} \\= 24.75 \: m {s}^{ - 1} + 16.50 \: m {s}^{ - 1} = v \\= v = 41.25 \: m {s}^{ - 1}$
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