Question

a bus is travelling at a speed of 72 km/h,the brakes are applied so as to produce a uniform retardation of 1.2 m/s find the distance it travels after applying brakes so that is completely stops

Answer 1

Answer:

500/3m

Explanation:

first we will onvert 72km/hr into m/s

72*5/18=20m/s

now we get u=20m/s

a=-1.2m/s

v=0

we apply formula vsquare =usquare +2as

0square=20 square+2*-1.2*s

0=400-2.4s

400/2.4=s

500/3m=s

Answer 2

Answer:

166.6

Explanation:

see we  are given a = -1.2m/s (retardation)

u = 72km/hr or 20m/s

the final velocity will be 0m/s

v=0m/s

putting this in v^2 = u^2 + 2as

0= 400 - 2.4s

-400 = -2.4s

s = 400/2.4

= 166.6 m