Math, asked by jagdeeshmauryasoron, 10 months ago

a bus leaves Nanda gun at 10:00 a.m. if it is a travelling at a speed of 45 kilometre per hour at what time will it reach Rajapur which is 270 kilometre away​

Answers

Answered by shivamsingh54
5

speed of the bus = 45 km/h

distance between Nanda gun and Rajapur

=270 km

speed = distance /time

=>45 km/ h = 270 km / time

=>(45 km / h) × time = 270 km

=> time = 270 km / (45 km / h)

=>time = 6 h

so,the bus will take 6 hours to reach Rajapur.

starting time of bus = 10:00 a.m.

so the time when bus reach Rajapur is

= 10:00 a.m + 6 hours

= 4:00 p.m.

ANSWER:

4:00 p.m.

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