Question

13. Prove that:
tan 0 cot 0
1 - tan e 1-cot 0
cos 0 + sin 0
cos 0 - sin o​

Answer 1

Answer:

tanθ

+

1−tanθ

cotθ

=

1−

tanθ

1

tanθ

+

1−tanθ

tanθ

1

=

tanθ−1

tan

2

θ

−

tanθ−1

tanθ

1

=

tanθ−1

tan

2

θ−

tanθ

1

=

tanθ(tanθ−1)

tan

3

θ−1

=

tanθ(tanθ−1)

(tanθ−1)(tan

2

θ+tanθ+1)

=

tanθ

tan

2

θ+tanθ+1

=tanθ+1+cotθ

=

cosθ

sinθ

+

sinθ

cosθ

+1

=1+

cosθ⋅sinθ

sin

2

θ+cos

2

θ

=1+

cosθsinθ

1

=1+secθ⋅cosecθ.

solution