Question

A bus moves from one station to another and waits there for 5 mints and again comes back to the same station. The distance between the two station is 15 km. And the total time taken for the journey is 30 minutes. What is the average speed of the bus?

Answer 1

total distance = 15 Km
total time = 30 mins = 1/2 hrs
average speed = total distance/total time
= 15 ÷ 1/2
= 15 × 2
= 30 kmhr^-1

Answer 2

distance =15km
time =0.5km(it should be converted to km)

speed = distance by time
speed=15/0.5
=30km per hr