Math, asked by nonstpdhamaka99021, 6 months ago

ABCD is a parallelogram where the baseDC is 6 cm and height is 4 cm. A rhombusAEFD is drawn on the sides AB and DCas shown in the figure. AF = 4.5 cm andDE = 7.5 cm. What is the area of theparallelogram EBCF?​please answer me it's urjent!!!!

Answers

Answered by NikhilBhan
4

Step-by-step explanation:

are of parallelogram = b*h = 4*6=24cm²

area of rohmbus = 1/2*D1*D2 = 16.875cm²

area of EBCF = 24 - 16.875 = 7.125 cm²

Answered by rajarajput1
0

Answer:

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