A Bus moves slowly on the road for 20 sec. with an acceleration of 4.2mls? before taking speed. How much es distance would it have covered on the road?
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Answered by
3
Explanation:
u =5m/sv=?a=0.2m/s
2
t=10sec
v=u+at
v=5+0.2×10
v=7m/s
Now distance traveled,
s=?
v
2
=u
2
+2as
7
2
=5
2
+2×0.2×s
49=25+0.4s
49−25=0.4s
s=
0.4
24
s=60m
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1
Answer:
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