A bus moves with a average speed of 60 kilometers per hours for 4.5 hours. Find the distance travelled by it.Please answer fast I will mark the best answer as brainiest answer.
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CBSE
Physics
Grade 11
Average speed and average velocity
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A bus moves with an average speed of 60 kilometers per hour for 4.5 hours. Find the distance traveled by it.
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Hint: Average speed is the ratio of total distance to the total time taken. It is given by the equation
vavg=xt
Where, x is the total distance and t is the time taken
Using this equation we can find the total distance travelled.
Complete step by step answer:
Given,
The average speed of the bus, vavg is 60km/hr.
1km is 1000m.
1hr is 60min.
1min is 60s.
∴1hr=60×60s=3600s
So, in order to convert 60km/hr into m/s we need to multiply the numerator by 1000 and denominator by 3600.
That is,
vavg=60km1hr=60×10001×3600=16.66m/s
Time taken is given as 45hr. Thus,
t=45hr=45×3600s=16200s
We need to find the distance travelled by the bus.
Average speed is the ratio of total distance to the total time taken. It is given by the equation
vavg=xt
Where x is the total distance and t is the time taken
From this we can calculate the distance as
x=vavg×t
Substitute the given values then we get
⇒x=16.666×16200
⇒x=269892m
⇒x=269.8km
x≈270km
Therefore, the distance traveled by bus is 270km.❤
Answer: Given: t=4.5 hours
V=60kmph
Distance travelled=V*T
=60*4.5
=270 km
Explanation: