Question

A bus moves with velocity 10m/s 1km away from a bike who wishes to overtake the bus in 60s what should be his velocity

Answer 1

Answer :-

$V{bi} = 26.66 m/s$

Given :-

velocity of bus is = 10 m/s

Distance b/w them is 1 km

t = 60s

To find :-

The velocity required to overtake the bus.

Solution:-

Let $V_b$ and $V_{bi}$ be the velocity of the bus and bike respectively.

Relative Velocity with respect to bus :-

→$V = \dfrac{1000}{60}$

→$V = 16.66 m/s$

Since,

They are moving in the same direction.

→$V = V_{bi} - V_{b}$

→$16.66 = V{bi} - 10$

→$16.66 +10 = V{bi}$

→$V{bi} = 26.66 m/s$

hence,

The required velocity to overtake the bus in 60 s will be 26.66 m/s.

Answer 2

hello there

Explanation:

Question: A bus moves with velocity 10m/s 1km away from a bike who wishes to overtake the bus in 60s what should be his velocity?

To find : The required velocity of the bike to overtake the bus.

Solution:

Given:

Speed of the bus = 10 m/s

Distance between them = 1 km

Also 1 km = 1000 m

Here,

Let the speed of the bike be = x m/s

[ As, According to the condition ]

■ Relative speed = (x-10) m /s

We ,know that :

$Distance = Speed \times Time$

Putting their respective values in the formulae

Thus,

■ 1000 m = (x - 10) ×60

■ 1000 m = 60x - 600

■ (1000 + 600 ) m = 60x

■ 60 x = 1600 m

■ x = (1600/60) m/s

■ x = 26.67 m/s

_____________________________

So, The velocity of the bike must be 26.67 m/s to overtake the bus in 60s.

_________________________________

Hope it helps

Thank you!