Question

A bus moving along a straight line at 40 m/s undergoes an acceleration of 5 m/s foe 2 seconds.Calculate the speed after 2 seconds.

Answer 1

GIVEN

A bus moving at speed of 40m/sec.

i.e. Initial speed (u) = 40m/sec

Acceleration (a) = 5m/sec^2

Time taken (t) = 2sec

TO FIND :- Final velocity (v)

SOLUTION :-

Acceleration is the rate of change in velocity per unit time.

FORMULA :-

$a = \frac{(v - u)}{t}$

where,

a = acceleration

v = final velocity

u = initial velocity

t = time taken

Now we can put the given values to get our answer :-

$a = \frac{v - u}{t} \\ \\ \\ \\ \implies 5 = \frac{v - 40}{2} \\ \\ \\ \\ \implies 5 \times 2 = v - 40 \\ \\ \\ \\ \implies 10 = v - 40 \\ \\ \\ \\ \implies v = 10 + 40 \\ \\ \\ \\ \implies \boxed{ \boxed{v = 50mps}}$

Hence the velocity of the bus after acceleration is 50m/sec.