Question

A bus moving with speed of 20m/s beings to slow at a constant rate of 3m/s each second. before each stopping it will cover

Answer 1

heya......

We'll first jot down the given points. Initial velocity is 20m/s i.e. u.

Final velocity would be zero since the bus stopped.

It is noted that the bus deccelartion of 3m/s, 

so the acceleration should be considered negative of 3m/s I.e. -3m/s. So using third law of motion i.e.

v^2 - u^2= 2as

(0)^2 - (20)^2= -2×3×s {Note here I used minus sign in acceleration}

-400= -6×s

s=400÷6

s=66.67 m

So bus would cover a distance of 66.67m before coming to rest.

tysm.......@kundan