a bus moving with velocity of 60km/h is bought to rest in 20 seconds by applying bteaks find the retardation
Answers
Answered by
0
V=0
u=60*5/18=50/3
t=20
by first equation of motion,
V=u+at
a=(v-u)/t
=(0-50/3)/20
=-5/6
so retardation=5/6=0.833
u=60*5/18=50/3
t=20
by first equation of motion,
V=u+at
a=(v-u)/t
=(0-50/3)/20
=-5/6
so retardation=5/6=0.833
Similar questions