Question

A bus of starting from rest moves with uniform aceelaration of 0.5 m/s2 for 2 minutes
Find (a) Speed
(b) Distance

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Answer 1

$\small{\underline{\sf{\purple{Given:–}}}}$

• Acceleration of the bus, a = 0.5 m/s²
• Time taken, t = 2 minutes

$\small{\underline{\sf{\purple{To\:find:–}}}}$

• Speed of the bus
• Distance travelled

$\small{\underline{\sf{\purple{Solution:–}}}}$

Time = 2 minutes = 120 seconds

We know that,

$\boxed{\bf{\red{V=u+at}}}$

.°. V = 0 + 0.5 × 120

V = 60 m/s

We also know that,

$\boxed{\bf{\red{S=ut+\frac{1}{2}at²}}}$

.°. S = 0 × 120 ×+ 1/2 (0.5) × (120)² m

.°. S = 3600 m

Hence, speed of the bus is 60 m/s

and distance travelled by bus is 3600 m

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