Question

A bus of starting from rest moves with uniform aceelaration of 0.5 m/s2 for 2 minutes
Find (a) Speed
(b) Distance

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Answer 1

$\;\;\underline{\textbf{\textsf{ Given:-}}}$

• Initial velocity, u = 0 m/s

• Acceleration, a = 0.5 m/s²

• Time, t = 2 min or 120 sec

$\;\;\underline{\textbf{\textsf{ To Find :-}}}$

•Final velocity, v

•Distance travelled, d

$\;\;\underline{\textbf{\textsf{ Solution :-}}}$

$\underline{\:\textsf{ Here, we know the formula :}}$

$\tt{v = u + at}$

$(\bf 1st\: equation \: of \: motion)$

$\underline{\:\textsf{Putting the given values :}}$

$\tt{ \longrightarrow v = 0 + 0.5 \times 120}$

$\tt{\longrightarrow v = 0 + 60}$

$\bf{ \longrightarrow v = 60 \: m/s}$

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$\underline{\:\textsf{Again, we know that :}}$

$\tt{s = ut + \dfrac{1}{2}a {t}^{2} }$

$(\bf 2nd \: equation \: of \: motion)$

$\underline{\:\textsf{Now, put the given values :}}$

$\tt{ \longrightarrow s = 0 \times 60 + \dfrac{1}{ \cancel{2}} \times 0.5 \times \cancel{60} \times 60 }$

$\tt{ \longrightarrow s = 0 + 1 \times 0.5 \times 35 \times 60}$

$\tt{\longrightarrow s = 0 + 0.5 \times 35 \times 60}$

$\bf{ \longrightarrow s = 1050 \: m}$

$\;\;\underline{\textbf{\textsf{ Hence-}}}$

$\underline{\textsf{Final velocity of the bus is \textbf{60m/s}}}.$

$\underline{\textsf{ The distance travelled by a bus is \textbf{1050m}}}.$

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$\;\;\underline{\textbf{\textsf{ Know More:-}}}$

$(\bf 1st\: equation \: of \: motion)$

•$\boxed{\sf v = u + at}$

$(\bf 2nd \: equation \: of \: motion)$

•$\boxed{\sf s = ut + \frac{1}{2} at^{2}}$

$(\bf 3rd \: equation \: of \: motion)$

•$\boxed{\sf v^{2} - u^{2} = 2as}$

Where,

›› s = Distance Covered

›› u = Initial Velocity

›› t = Time taken

›› v = Final Velocity

›› a = Acceleration

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Answer 2

Answer:

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Explanation:

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