Question

A bus of starting from rest moves with uniforn acceleration of 0.1m/s2 for 2min find

Answer 1

Initial velocity ( u ) = 0

Acceleration ( a ) = 0.1 m/s²

Time ( t ) = 2 min = 2 × 60 s = 120 s

Final velocity ( v ) = ?

Distance traveled ( s ) = ?

Using equation of Motion,

 ⇒ v = u + at

 ⇒ v = 0 + ( 0.1 m/s² ) × 120 s

 ⇒ v = 120 ms / 10 s²

 ⇒ v = 12 m/s.

Since the bus is moving along a straight line in a certain direction,so speed = velocity.

Hence , speed acquired = 12 m/s.

Now,

⇒ s = ut + ( at² )/2

⇒ s = ( 0 × 120 s ) + { ( 0.1 m/s² ) ( 120 s )² ) / 2

⇒ s = 0 + { ( 1 m / 10 s² ) ( 120 s × 120 s ) } ÷ 2

⇒ s = ( 12 × 120 m ) ÷ 2

⇒ s = 720 m.

Hence , speed acquired = 12 m/s and distance traveled = 720 m.

Answer 2

$\huge\mathfrak{Bonjour!!}$

$\huge\bold\green{Answer:-}$

✿ Here, u= 0, a= 0.1 m s^-2, t= 2 min =120s

a) v= u+ at

= 0 +0.1 ×120 = 12 m/s .

b) s= ut + 1/2 at²

= 0 × 120 + 1/2 × 0.1 × (120)² = 720 m.

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Hope it helps...:-)

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