What is the mass of glucose required to produce 44 g of CO2 on complete combustiom
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Answered by
14
We know that mass of glucose 180g.
Mass of CO2 formed in reaction is 44 x 6 =264
therefore glucose required is 180 x 44/264 =30 g
Mass of CO2 formed in reaction is 44 x 6 =264
therefore glucose required is 180 x 44/264 =30 g
Answered by
6
by balanced chemical equation,
6 moles of co2 requires for completely combustion of glucose
so for 6 mole of carbon dioxide one mole of glucose is required
for 1 mole means 44 gram of co2
we need 180/6 grams of glucose
that means 30 gram of glucose
I hope it helps
6 moles of co2 requires for completely combustion of glucose
so for 6 mole of carbon dioxide one mole of glucose is required
for 1 mole means 44 gram of co2
we need 180/6 grams of glucose
that means 30 gram of glucose
I hope it helps
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