Question

A bus running at a speed of 18km/h is stopped in 2.5second by applying brakes. calculate the retardation produced and and the distance travelled

Answer 1

final velocity(v)= 0 m/s
initial velocity(u)= 18 km/h= 5 m/s
time(t)= 2.5 sec
retardation(a)=?
v=u+at
0=5+a x 25/10
0=5+25a/10
-25a/10=5
-25a=50
a=50/25
retardation=2m/s

Answer 2

Answer:

Explanation:

Known terms:-

u = Initial speed

v = Final speed

a = Acceleration

r = Retardation

t = Time

Given:-

Initial speed of bus, u = 18 km/h = 5/18 × 18 = 5 m/s

Time taken by bus to stop after applying brakes, t = 2.5 sec

Final speed of bus, v = 0 m/s (Because when brakes applied then bus stops)

To Calculate:-

Retardation Produced.​

Formula to be used:-

Motion 1st equation that is v = u+at

Solution:-

Putting all values, we get

⇒  v = u + at

⇒ 0 = 5 + a(2.5)

⇒ a =  -5/2.5

⇒ a = - 2 m/s²

Hence, Retardation Produced by bus is  2 m/s².