Math, asked by surya9628, 1 year ago

solve it please 19no

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Answered by yoodi

Atq
let X be numerator and Y be denominator
$x + y = 8 \\ x + 3 \div y + 3 = 3 \div 4 \\ by \: solving \: these \: two \: equation \: i.e \\ x + y = 8 \\ 4x - 3y = - 3 \\ we \: get(x \: = 3) \: and(y = \: 5) \\ hence \: required \: fraction \: is3 \div 5$
here is your answer

yoodi: please mark as brainyliest

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