a bus running at a speed of 18kmph is stopped in 2.5 sec by applying brakes . calculate the retardation produced .
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u = 18 km/h = 18×(5/18) = 5m/s
v= 0m/s
t= 2.5 sec
using first equation of motion
v=u+at
0= 5+ a(2.5)
-5=2.5a
a= -5/2.5 => -2 m/s²
note => retardation is 2 m/s² and acceleration is -2m/s²
hope this helps
v= 0m/s
t= 2.5 sec
using first equation of motion
v=u+at
0= 5+ a(2.5)
-5=2.5a
a= -5/2.5 => -2 m/s²
note => retardation is 2 m/s² and acceleration is -2m/s²
hope this helps
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