What is the magnitude of the gravitational force exerted by a 15 kg mass on a 25 kg mass seperated by a distance of 25 cm .what is the acceleration produced on each mass?
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You can use newton's gravitational formula:
F=(Gm1m2/d^2)Newtons, where,
F:Force Of Attraction
G:Newton's Gravitational Constant
m1:Mass of body 1(in kg)
m2:Mass of body 2(in kg)
d:Distance between them(in metres)
Now, Substituting the values,
F = (6.673x10^-11x15x25)/(0.25x0.25) N
=(6.673x10^-11 x 375)/(0.0625)N
=(2502.375x10^-11)/(0.0625)N
=40038 x 10^-11 N
From here, we can use Newton's second law F=ma to find acceleration.
Now, force on the two bodies will be the same. the difference will be in the mass.
For 15 kg Mass:a=F/m
=40038 x 10^-11/15
=2669.2 x 10^-11 m/s^2
Similarly, For 25 kg mass:a=F/m
= 40038 x 10^-11/25
= 1601.52 x 10^-11 m/s^2
F=(Gm1m2/d^2)Newtons, where,
F:Force Of Attraction
G:Newton's Gravitational Constant
m1:Mass of body 1(in kg)
m2:Mass of body 2(in kg)
d:Distance between them(in metres)
Now, Substituting the values,
F = (6.673x10^-11x15x25)/(0.25x0.25) N
=(6.673x10^-11 x 375)/(0.0625)N
=(2502.375x10^-11)/(0.0625)N
=40038 x 10^-11 N
From here, we can use Newton's second law F=ma to find acceleration.
Now, force on the two bodies will be the same. the difference will be in the mass.
For 15 kg Mass:a=F/m
=40038 x 10^-11/15
=2669.2 x 10^-11 m/s^2
Similarly, For 25 kg mass:a=F/m
= 40038 x 10^-11/25
= 1601.52 x 10^-11 m/s^2
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