Question

A bus start from rest and attain a velocity of 20 m/s in 5 sec. Find the acceleration of the bus​

Answer 1

Required Answer :

Acceleration of the bus = 4 m/s²

Given :

• Initial velocity of the bus = 0 m/s [Because it started from rest.]
• Final velocity of the bus = 20 m/s
• Time = 5 seconds

To find :

• Acceleration of the bus

Solution :

To calculate the acceleration of the bus, we will use the first equation of motion.

First equation of motion :

• v = u + at

where,

• v denotes the final velocity
• u denoted the initial velocity
• a denotes the acceleration
• t denotes the time taken

Substituting the given values :

⇒ 20 = 0 + (a)(5)

⇒ 20 = a × 5

⇒ 20/5 = a

⇒ 4 = a

Acceleration of the bus = 4 m/s²

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★ Some technical terms :

• Acceleration is the rate of change of velocity.
• Velocity is the distance travelled by a body in one second in a particular direction.

★ Equations of motion :

First equation of motion :-

• v = u + at

Second equation of motion :

• s = ut + ½ at²

Third equation of motion :

• v² - u² = 2as

Answer 2

Answer:

$\large \green {\boxed {\sf acceleration \: \: a = 4\: m {s}^{ - 2} }} \:$

Explanation :

Given,

$\sf \odot \: initial \: velocity \: \: u = 0 \: m {s}^{ - 1} </p><p> \\ \\ \odot \: \sf final \: velocity \: \: v = 20 m {s}^{ - 1} \\ \\ \sf \: \odot \: time \: t = 5 \: s\\ \\ </p><p></p><p> \sf \: \pink{acceleration \: \: a = to \: find }$

Formula :

$\large \pink {\boxed { \sf\: acceleration \: \: a = \frac{v - u}{t} }}$

Solution :

$\large \sf \: \: \: a = \frac{20- 0}{5} \\ \: \: \: \: \: \: \: = \frac{20}{5} \\ \sf \: \: \: \: \: \: \: = 4 \: m {s}^{ - 2} \\ \\ \large \green {\boxed {\sf \therefore \: acceleration \: \: a = 4\: m {s}^{ - 2} }}$