A bus start from rest. If the acceleration in 2m/s square, find the distannce travelled and the velocity after 2 seconds.
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1
Answer:
7
Explanation:
the velocity after 2 sec is
v=u+a/t
v=0+2into 2=4
distance[s] can found through
v square=u square +2into a into s
4*2=0*2+2*2*s
16=0+4s
s=4 m
[s]=ut+ 1/2 at sq
s=0 1/2 *2*2 sq
=1*2*2
so; s=4;;;;;;;;;;;;;;
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