Physics, asked by parajuliprashant100, 7 months ago

A bus start from rest. If the acceleration is 2m/s^2,find

i. the distance travelled.
ii. the velocity after 2 seconds

who will write this answer fast he/she will be brainlist..​

Answers

Answered by gargidubey2020
1

Answer:

1 is incomplete question

2. v=u+at

v=0+(2m/s²)(2)

v=4m/s²

Answered by Anonymous
4

Answer:

given-

u= 0

a= 2m/sec^2

t=2 sec

_________________________

To find -

distance travelled=?

velocity=?

_________________________

_________________________formula used

s= ut +1/2 at^2

v=u+at

________________________

solution-

v= u+at

v= 0+ 2 x 2

v= 4m/sec

s= ut +1/2 at^2

s= 0x t+ 1/2 x 2 x 2^2

s= 1/2 x 8= 4 metre

distance travelled is 4 metre and velocity is 4 m/secl

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