Question

a bus start from the rest and pick up a velocity of 90 km/ h in 1/2 min .calculate the uniform acceleration of the bus in m/s​

Answer 1

Given,

$\vec{u}$ = 0 m/s

$\vec{v}$ = 90 km/h = 25 m/s

Time (t) = ½ min = ½ × 60 s = 30 s.

We know,

$a = \frac{∆v}{∆t}$

∴ a = (25 m/s - 0 m/s)/(30 s) = ⅚ m/s²

⇒ a = 0.83 m/s² (approx).

∴ Acceleration of the particle was of 0.83 m/s².

More:-

Equations of linear kinematics:-

1. $v = u + at$
2. $S = ut + \frac{1}{2} at^2$
3. $2aS = v^2 - u^2$
4. $S_{nth} = u + \frac{a}{2} (2n - 1)$

Answer 2

$\bold{Answer\;:-}$

Given :-

• A bus start from the rest, which means initial velocity of the bus, u = 0 m/s

• Final velocity of the bus, v = 90 km/h = 90*1000/60*60 = 25 m/s

• Time taken, t = ½ minute = 30 s

Therefore, acceleration, a = change in velocity/time = v-u/t

• a = 25/30

• a = 5/6 = 0.833.. or 0.84 m/s²

$\bold{Hope\;it \; helps\;!}$