Question

A bus started from A to B then after covering two third distance some fault occurs. Driver mentioned the fault quickly
and bus will move again. But now the speed of the bus is reduced by one third and for this reason bus reaches at B
late by 1 hour what was the actual time in going B from A.
(1) 6.30 hr
(2) 7 hr
(3) 6 hr
11. A bus from A to started with th
(4) 6.45 hr
(5) 7.30 hr
from A to B started with the speed of 80​

Answer 1

Step-by-step explanation:

Train proceeds at 3/4 S where S is his usual speed means 1/4 decrease in the speed which will lead to 1/3 increase in the time.

[ As S *T = D, Speed is inversely proportional to time when distance is constant].

Now, the main difference come in those 24 km and the change in difference of time = 35 - 25 = 10 m

= 1 / 3 *T = 10 where T is the time required to cover the distance of (50 - 74) = 24 km

T = 30 min = 0.5 hours

• Speed of the train = 24 / (0.5) = 48 kmph