A bus starting from a stationery position and on 10 minutes goes up to 36 km/h find its acceleration
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Since the bus starts from stationary position its initial vel. 0 m s-1
time taken to reach final vel. = 10 min. or 10× 60 seconds.= 600 sec.
final velocity= 36km hr-1 or 36 × 5/18.
= 10 m s-1.
now. from equation of motion :-


hope it helps!
time taken to reach final vel. = 10 min. or 10× 60 seconds.= 600 sec.
final velocity= 36km hr-1 or 36 × 5/18.
= 10 m s-1.
now. from equation of motion :-
hope it helps!
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