Question

solve it plzz......

note : only do (c) no. /ans is 17 ​

Answer 1

a+b=5 ———————(1)

Using (a+b)^2=a^2+b^2+2ab

=> 25=a^2+b^2+2×2

=> 25–4=a^2+b^2 = 21

Since (a-b)^2=a^2+b^2-2ab

Thus (a-b)^2=21–2×2=21–4=17

Thus a-b= (17)^1/2 —————(2)

Adding eqn (1) and (2),we get

2a=5+(17)^1/2

Thus a= [5+(17)^1/2]/2

And subtracting eqn (2) from (1) , we get

2b=5-(17)^1/2

Thus b=[5-(17)^1/2]/2

Hence a= [5+(17)^1/2]/2 and b=[5-(17)^1/2]/2

Answer 2

Step-by-step explanation:

(a-b)²= a²+b²-2ab

(a-b)²= 21-2×2. ( you get the value of a²+b² by doing the b question)

(a-b)²= 21-4

(a-b)²= 17

hope this helps you .

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