Question

A bus starting from rest accelerates in a straight line at a constant rate of 4 m/s2

for 5 sec. Calculate

the distance travelled by the bus during this time interval.​

Answer 1

Answer:

Explanation:

s = 96 m

Explanation:

GIVEN :

u = 0 m/s  

a = 4 m/s^2

t  =  5sec

s = ?

s = ut + 1/2 at^2

s = 0*5 + 1/2*4*5*5

0   +  2*25

s = 50 m

Thank you

Answer 2

Answer:

s= 50 m

Explanation:

ACCELERATION(a)= 4M/S^2

TIME(t) =5 SEC

INITIAL VELOCITY (u) = 0

DISTANCE(s) =?

s =ut + 1/2at^2

s= 0×5 + 1/2×4× (5)^2

s=2 × 25

s= 50 m

HOPE IT HELPS YOU