Three coins are tossed no of sample space for getting head in the second place?
Answers
Answer:
The sample space of a fair coin flip is {H, T}. The sample space of a sequence of three fair coin flips is all 23 possible sequences of outcomes: {HHH,HHT,HTH,HTT,THH,THT,TTH,TTT}.
Breaking down probability questions to purely math is a surefire way to torture your mind. Translating these questions into more intuitive math may help you reason through questions far more easily.
Think of it like this: You can either get 0 heads, 1 heads, 2 heads, or 3 heads. This will also yield 3 tails, 2 tails, 1 tails, and 0 tails, respectively. Now notice that the ratios are symmetric due to the fact that there are only two possible outcomes; 0:3, 1:2, 2:1, 3:0.
Remember that the probability of either heads or tails is equal, and that fact coupled with the symmetric distribution of outcomes, and you can deduce that P(2:1)+P(3:0)=P(0:3)+P(1:2) . Since these are the only four options we may conclude that the probability of getting at least two heads when tossing three fair coins is 1/2.
Probability is hard. Luckily, people have a natural intuition for simple probability. Just figure out how to organize the information to best understand it. ALSO, the hardest part of probability theory for me was the notation, so do get on learning that before you worry about the actual calculation. I feel that you’ll find it much easier that way.