Question

A bus starting from rest grains an acceleration of5m/s²in 3 s.Find the distance travelled by bus in 3s.​

Answer 1

Provided that:

• Initial velocity = 0 m/s
• Acceleration = 5 m/s sq.
• Time = 3 seconds
• Distance = ???

Knowledge required:

→ The second equation of motion is given by, s = ut + ½ at²

• Where, s denotes distance, u denotes initial velocity, a denotes acceleration and t denotes time.

Required solution:

→ s = ut + ½ at²

→ s = 0(3) + ½ × 5 × (3)²

→ s = 0(3) + ½ × 5 × 3 × 3

→ s = 0(3) + ½ × 5 × 9

→ s = 0 + ½ × 5 × 9

→ s = 0 + ½ × 45

→ s = 0 + 22.5

→ s = 22.5 m

→ Distance = 22.5 m

• Distance = 22.5 metres

Additional information:

The difference between distance and displacement is mentioned below -

$\begin{gathered}\boxed{\begin{array}{c|cc}\bf Distance&\bf Displacement\\\frac{\qquad \qquad \qquad\qquad\qquad \qquad\qquad\qquad}{}&\frac{\qquad \qquad \qquad\qquad\qquad \qquad\qquad\qquad}{}\\\sf Path \: of \: length \: from \: which &\sf The \: shortest \: distance \: between \\ \sf \: object \: is \: travelling \: called \: distance. &\sf \: the \: initial \: point \: \& \: final \\ &\sf point \: is \: called \: displacement. \\\\\sf It \: is \: scalar \: quantity. &\sf It \: is \: vector \: quantity \\\\\sf It \: is \: positive \: always &\sf It \: can \: be \: \pm \: \& \: 0 \: too \end{array}}\end{gathered}$