Question

A bus starting from rest moves with a u uniform acceleration of 0.1m/s² for 2min .find the distance travelled.​

Answer 1

Given

• Initial velocity (u) = 0 {rest position}
• Acceleration (a) = 0.1m/s²
• time taken (t) = 2min = 2 × 60 = 120s

To Find

• Distance travelled

Solution

As we know that

→ s = ut + ½ at² {2nd equation of motion }

→ s = 0 × 120 + ½ × 0.1 × 120 × 120

→ s = 0.1 × 60 × 120

→ s = 720m

Hence,

• Distance travelled by bus is 720m

Extra Information

• Force = mass × acceleration
• v = u + at {First equation of motion}
• v² = u² + 2as {third equation of motion}
• Pressure = Force/Area

Answer 2

Given :-

• Initial speed of the bus = 0 m/s
• Acceleration = 0.1 m/s²
• Time taken, t = 2 minutes = 120 s

$\rule{200}{2}$

To Find :-

• Distance travelled.

$\rule{200}{2}$

Solution :-

Distance travelled.

⇒ (12)² - (0)² = 2(0.1) s

⇒ s = 720 m

Hence, Speed acquired finally by the bus is 12 m/s.

And Distance travelled by the bus is 720 m.

$\rule{200}{2}$