Question

A bus starting from rest moves with a uniform acceleration of 0.1Ms for 2minutes find (a) the speed acquire,(b) the distance traveled​

Answer 1

Answer:

a) 12m/s b) 720m

Explanation:

v=u+at

v=0+0.1×60×2

v=12m/s

v^2-u^2=2as

144=.2s

s=720m

Answer 2

Answer:

Given

Initial velocity (u) = 0 {rest position}Acceleration (a) = 0.1m/s²time taken (t) = 2min = 2 × 60 = 120s

To Find

Distance travelled

Solution

As we know that

→ s = ut + ½ at² {2nd equation of motion }

→ s = 0 × 120 + ½ × 0.1 × 120 × 120

→ s = 0.1 × 60 × 120

→ s = 720m

Hence,

Distance travelled by bus is720m

Extra Information

Force = mass × accelerationv = u + at {First equation of motion}v² = u² + 2as {third equation of motion}Pressure = Force/Area