Question

A bus starting from rest moves with a uniform acceleration of 0.1m/s^2 for 2 minutes. Find the speed required and the distance travell

Answer 1

Answer:

u=0

a=0.1m/sec

t=(2×60)sec

at-u=v

(0.1×60×2)-0=v

12m/sec=v

Answer 2

$\Large{\textbf{\underline{\underline{According\;to\;the\;Question}}}}$

Initial Speed = (0 m/s)

Acceleration = (0.1 m/s²)

Time taken = 2 minutes

Convert it into second :-

Time taken = 120 second

Now,

Using 1st Equation of motion :-

v = u + at

⇒ v = 0 + 0 × 1 × 120

⇒ v = 12 m/s

Also,

Using 3rd Equation of motion :-

v² - u² = 2as

(12)² - (0)² = 2(0.1)s

144 = 0.2s

144/0.2 = s

s = 720 m

Therefore, we get :-

Speed = 12 m/s.

Distance = 720 m.